如何在 Django 中实现分页

Posted on Wed, 25 Dec 2024 11:07:31 +0800 by LiangMingJian

Paginator #

在 Django 中，用户可以在view.py文件中通过创建类Paginator(list, int)来对数据表进行分割，然后通过.page(1)方法实现分页。

示例 #

在view.py文件中设置。

from django.core.paginator import Paginator, EmptyPage, PageNotAnInteger
from django.shortcuts import render
 
def listing(request):
    contact_list = Contacts.objects.all()
    paginator = Paginator(contact_list, 25) # Show 25 contacts per page
 
    page = request.GET.get('page')
    try:
        contacts = paginator.page(page)
    except PageNotAnInteger:
        # If page is not an integer, deliver first page.
        contacts = paginator.page(1)
    except EmptyPage:
        # If page is out of range (e.g. 9999), deliver last page of results.
        contacts = paginator.page(paginator.num_pages)
 
    return render(request, 'list.html', {'contacts': contacts})

在Example.html文件中调用。

{% for contact in contacts %}
    {# Each "contact" is a Contact model object. #}
    {{ contact.full_name|upper }}<br />
    ...
{% endfor %}
 
<div class="pagination">
    <span class="step-links">
        {% if contacts.has_previous %}
            <a href="?page={{ contacts.previous_page_number }}">previous</a>
        {% endif %}
 
        <span class="current">
            Page {{ contacts.number }} of {{ contacts.paginator.num_pages }}.
        </span>
 
        {% if contacts.has_next %}
            <a href="?page={{ contacts.next_page_number }}">next</a>
        {% endif %}
    </span>
</div>